1.

In the expansion of `(1+x)^(50),`find the sum of coefficients of odd powers of `xdot`

Answer» Correct Answer - `2^(49)`
We have,
`(1+x)^(50) = .^(r=0)overset(5)sum.^(50)C_(r )x^(r )`
Therefore, sum of coefficient of odd powers of x is
`.^(50)C_(1) + .^(50)C_(3) + "……" + .^(50)C_(49) = (1)/(2) (2^(50)) = 2^(49)`


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