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In the expansion of `(1+x)^n ,`7th and 8th termsare equal. Find the value of `(7//x+6)^2`. |
Answer» Correct Answer - `n^(2)` Since the `7^(th)` and `8^(th)` terms are equal , we have `.^(n)C_(6)x^(6) =.^(n)C_(7)x^(7)` or `x=(.^(n)C_(6))/(.^(n)C_(7))=(7)/(n-6)` or `(7/x+6)=n^(2)` |
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