InterviewSolution
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InterviewSolution
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In the experiment of calibration of voltmeter, a standard cell of emf `11 V` is balanced against `440 cm` of potentiometer wire. The potentail difference across the ends of a resistance is found to balance aginst `220 cm` of the wire. The corresponding reading of the voltmeter is `0.5 V`. Find theerror in the reading of voltmeter. |
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Answer» `k= (E_(B))/(L) = (1.1)/(440) = 0.0025 Vcm^(-1)` potential difference across `R` is `0.0025 xx 220 = 0.550 V` Error in the reading of voltmeter is reading of voltemetre - reading of potentional `= 0.5 - 0.55 = - 0.05 V` |
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