1.

In the figure a hemispherical bowl of bowl of radius R is shown Electric field of intensity E is present perpendicular to the circular cross section of the hemisohere.

Answer»

The MAGNITUDE of electric FLUX through the hemispherical surface in SITUATION I will be `EPIR^(2)`
The magnitude of electric flux through the hemispherical surface in surface II will be `2EpiR^(2)`
the magnitude of electric flux through the hemispherical surface in situation II will be `(EpiR^(2))/2`
the magnitude of electric flux through the hemispherical surface in situation II will be zero.

Answer :b,d


Discussion

No Comment Found

Related InterviewSolutions