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In the figure AB=AC and Z ACD=115°. Find Z A. plese tell fat and correct plese |
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Answer» In TRIANGLE ABC, AB=ACso,angle ABC=. angle ACBhere angle ACD=115°so, angle ACB=(180-115)°=65°so, angle ABC=65°sum of the three ANGLES of a triangle is 180°angle ABC+angle ACB+angle BAC=180°65°+65°+angle BAC=180°angle BAC=(180-130) °=50°so, angle A=50° |
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