1.

In the figure AB and BK represents incident and reflected rays. If angle BCF=theta then /_BFP will equal to

Answer»

`THETA`
`2THETA`
`3theta`
`3.5 theta`

Solution :(b) Here, incident RAY is PRALLEL to principal axis, so
`/_AMN=/_BCF=theta`
also `/_CBF=/_KMN=/_AMN`
`:. /_BFP=theta+/_CBF=theta+theta=2theta`


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