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In the figure ABCD, AB parallel to CD and the distance between them is 8 cm?AB = 12 cm, CD = 10 cm. Compute the area of quadrilateral (trapezium) ABCD? |
Answer» Area = \(\frac{1}{2}\) x DE x (AB + CD) = \(\frac{1}{2}\) x 8 x (10 + 12) = 4 x 22 = 88 cm2 |
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