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In the figure AD and BC intersect at E if AB = DE and BD = CE prove that AB equal to CD |
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Answer» and △ECDAB=CD [GIVEN]∠B=∠D [ANGLES in the same SEGMENT]∠A=∠C [Angles in the same segment]∴△EAB≅△ECD [ASA CRITERIA]∴BE=DE [CPCT]and AE=CE [CPCT] |
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