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In the figure AX & CY are respectively the bisectors of the opposite angles A & C of a parallelogram ABCD. Show that AX || CY |
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Answer» ∠A = ∠C (Opposite angles of parallelogram ABCD) Therefore, 1/2 ∠A = 1/2 ∠C i.e., ∠YAX = ∠YCX (1) Also, ∠AYC + ∠YCX = 180º (Because YA || CX) (2) Therefore, ∠AYC + ∠YAX = 180º [From (1) and (2)] So, AX || CY (As INTERIOR angles on the same SIDE of the transversal are supplementary) |
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