1.

In the figure, BEST is a rhombus, then the value of y – x is(a) 40° (b) 50° (c) 20° (d) 10°

Answer»

(a) 40° 

From the given figure TS ∥ BE and also BS is transversal line.

By the rule of alternate interior angles, ∠EBS = ∠BST = 40o

Then, ∠y = 90o … [∵diagonal bisect at 90o]

Consider triangle TSO,

By the rule of exterior angle property of triangle

∠STO + ∠TSO = ∠SOE

x + 40o = 90o

x = 90o – 40o

x = 50o

So, the value of y – x is = 90o – 40o = 50o



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