1.

In the figure BP : PQ : QC = 1 : 2 : 1. Area of triangle APQ is 8 sq.cm. a. Find the area of triangle ABP. b. Find the area of triangle ABC.

Answer»

a. BP : PQ = 1:2

Area of ∆ ABP is half the area of ∆ APQ.

Area of ∆ ABP = \(\frac{1}{2}\times8=4\) sq.cm

b. Area of ∆ ABC = 4 + 8 + 4 = 16 sq.cm



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