1.

In the figure, diagonals AC and BD of a trapezium ABCD with AB//DC intersect each other at ‘O’. Prove that ar (ΔAOD) = ar (ΔBOC)

Answer»

Given that AB // CD 

Now ΔADC and ΔBCD are on the same base and between the same parallels AB // CD. 

∴ ΔADC = ΔBCD 

⇒ ΔADC – ΔCOD = ΔBCD – ΔCOD 

⇒ ΔAOD = ΔBOC [from the figure]



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