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In the figure given below, find the (a) equivalent capacitance of the network between points A and B. Given: C_(1)=C_(5)=8muF, C_(2)=C_(3)=C_(4)=4muF. (b) maximum charge supplied by the battery, and (c ) total energystored in the network. |
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Answer» Solution :(a) In the network capacitors `C_(1) and C_(2)` as well as `C_(4) and C_(5)` are short CIRCUITED and do not contribute to equivalent capacitance of the circuit. `therefore` Equivalent capacitance `C=C_(3)=4MUF`. (b) `therefore` Charge supplied by the battery `Q=CV=(4muF)XX 7V=28muC` (c ) Total energy stored in the network `U=(1)/(2) CV^(2)=(1)/(2)(4F)xx(7V)^(2)=98muJ` |
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