In the figure given below, the position - time graph of a particle of mass 0.1 kg is shown. Find impulse at t=2sec.

In the figure given below, the position - time graph of a particle of

1.	In the figure given below, the position - time graph of a particle of mass 0.1 kg is shown. Find impulse at t=2sec.
Answer» SOLUTION :`v=(DX)/(dt)=4/2 = 2m//s ` velocity between t=0 sec to t =2 sec = 2 m/s velocity at 2 sec = 0 m/s Impulse = change in LINEAR momentum `=m(V_f - V_i) =0.1(0-2) = -0.2 kg ms^(-1)`

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In the figure given below, the position - time graph of a particle of mass 0.1 kg is shown. Find impulse at t=2sec.

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