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In the figure, light is incident on the thin lens as shown. The radius of curvature for both the surface is R. Determine the focal length of this system. |
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Answer» Solution :Forrefractionat firstsurface , `(mu_2)/(v_i)-(mu_1) /(-oo) = (mu_2 -mu_1)/(+R ) `…..(i) for refraction at `2^(ND) ` surface, ` (mu_3)/(v_2) -(mu_2)/(v_1) =(mu_3 - mu_2)/(+R) `….(II)  Addingequation(i) and (ii) we get `(mu_3)/(v_2) = (mu_3 -mu_1)/(R ) or v_2 = (mu_3 R)/( mu_3 -mu_1)` Therefore, focallengthof thegivenlenssystemis`(mu_3 R )/( mu_3 -mu_1)` |
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