1.

In the figure line AB is parallel to CD. If AB = 5cm, AC = 4cm and ∠CAB = 90°.a. Calculate the area of triangle ABC.b. How much is the area of triangle ∆ ABD?Write reason

Answer»

a. Area of ∆ ABC = \(\frac{1}{2}\) x 5 x 4 = 10 sq.cm

b. Area of ∆ ABD = Area of ∆ ABC 

Triangles with the same base and the third vertex on a line parallel to the base, have the same area.

Area of ∆ ABD = 10 sq.cm



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