1.

In the figure, \(\overrightarrow{BF}\) is the bisector of ∠ABC thenA) ∠ABF = ∠CBF B) ∠ABF = ∠ABC C) ∠ABF + ∠CBF = 90° D) ∠ABF + ∠CBF = 180°

Answer»

Correct option is (A) ∠ABF = ∠CBF

\(\overrightarrow{BF}\) is bisector of \(\angle ABC,\)

\(\therefore\) \(\angle ABF=\angle CBF=\frac{\angle ABC}2\)

A) ∠ABF = ∠CBF



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