1.

In the figure, P is the midpoint of AB and CD. a) Which angle has the same measure as that of angle APC ? b) Prove that AC = BD . c) Prove that BD is parallel to AC B A​

Answer»

. In quadrilateral ABCD we have

AC = AD

and AB being the bisector of ∠A.

Now, in ΔABC and ΔABD,

AC = AD

[GIVEN]

AB = AB

[Common]

∠CAB = ∠DAB [∴ AB bisects ∠CAD]

USING SAS criteria, we have

ΔABC ≌ ΔABD.

CORRESPONDING parts of congruent TRIANGLES (c.p.c.t) are equal.

∴ BC = BD.



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