1.

In the figure S_(1)and S_(2)are identical springs. The oscillation frequency of the mass m is f. If one spring is removed, the frequency will become

Answer»

f
`f//sqrt(2)`
`f xx 2`
`f xx sqrt(2)`

SOLUTION :In case of spring, frequency `=1/(2PI) sqrt(K/m)`
As per question, the two springs are in PARALLEL in horizontal position, EFFECTIVE force constant = 2K,
`f=1/(2pi) sqrt((2K)/m), , f. =1/(2pi) sqrt(K/m)`
When ONE spring is removed, `f.= f/sqrt(2)`


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