1.

In the figure shown

Answer»

the ratio of ENERGY DENSITY in `I^(st)` dielectric to second dielectric is `(5)/(3)`
the ratio of energy density in `I^(st)` dielectric to second dielectric is `(1)/(1)`
total INDUCED surface charge on the interface of the two dielectric is `(2sigma)/(15)`
total induced surface charge on the interface of the two dielectric is `-(2sigma)/(15)`

SOLUTION :(i)`(e_(1))/(e_(2))=(in_(1)E_(1)^(2))/(in_(2)E_(2)^(2))=(k_(1)E_(1)^(2))/(k_(2)E_(2)^(2))=((k_(1))/(k_(2)))((k_(1))/(k_(2)))^(2)=(k_(2))/(k_(1))=(5)/(3)`
(ii) `sigma_(B)=sigma(1-(1)/(k_(1)))-sigma(1-(1)/(k_(2)))=sigma((1)/(k_(2))-(1)/(k_(2)))=-(2sigma)/(15)`


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