1.

In the figure shown in key is switched on a t = 0. Let I_(1) and I_(2) be the current through inductors having self inductances L_(1) and L_(2) at any time t respectively. The magnetic energy stored in the inductors 1 and 2 be U_(1) and U_(2). Then U_(1)//U_(2) at any instant of time is

Answer»

`(L_(2))/(L_(1))`
`(L_(1))/(L_(2))`
`(I_(1))/(I_(2))`
`(I_(2))/(I_(1))`

Solution :As INDUCTORS are in parallel, so
`e_(1)=e_(2)`or `L_(1)(di_(1))/(dt)=L_(2)(di_(2))/(dt)RARR L_(1)i_(1)=L_(2)i_(2)`
Now `(U_(1))/(U_(2))=(e_(1)i_(1))/(e_(2)i_(2))=(i_(1))/(i_(2))=(L_(2))/(L_(1))`


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