Saved Bookmarks
| 1. |
In the figure shown in YDSE, a parallel beam of light is incident on the slit from a medium of refractive index n_1. The wavelength of light in this medium is lambda_(1). A transparent glass of thickness t and of refractive index n_(3) is put in front of one of the slits. The medium between the screen and the plane of the slits is n_(2). The phase difference between the light waves reaching point .O. (symmetrically relative to the slit is |
|
Answer» SOLUTION :`PHI= (2PI)/(lambda_2)((n_3)/(n_2)-1)t= (2pi)/(n_(1)lambda_(1))n_(2)((n_(3)-n_(2))/(n_2))t` `(therefore n_(1)lambda_(1)= n_(2)lambda_(2))""phi= (2pi)/(n_(1)lambda_(1))(n_(3)-n_(2))t`. |
|