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In the figure shown, the coefficient of friction between the two blocks is 0.1 and coefficient of friction between the block B and ground is 0.2, masses of A and B are 20kg and 40kg respectively. where a_(A)= acceleration of A and a_(B)= acceleration of B. {:(,"Column I",,"Column II"),((A),F=50N,(P),a_(A)=0m//s^(2)),((B),F=150N,(Q),a_(A)=0.5m//s^(2)),((C),F=200N,(R),a_(B)=0.5m//s^(2)),(,,(S),a_(B)=1.5m//s^(2)):} |
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Answer» Solution :`f_("max")` between A and B `rArr0.1xx200rArr20N` `f_("max")` between A and GROUND `rArr0.2xx600=120N` `F=50N a_(A)=a_(B)=0 m//sec^(3)` `F=150N a_(A)=a_(B)=0.5 m//sec^(2)`  F=200N `a_(A)=1m//sec^(2) a_(B)=1.5m//sec^(2)` |
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