In the figure shown two loops ABCD & EFGH are in the same plane.The smaller loop carries time varying current I=b t, where b is a positive constant and t is time.The resistance of the smalller loop is r and that of the larger loop is R.:(Neglect the self inductance of large loop) The magnetic force on the loop EFGH due to loop ABCD is (mu_(0)^(2) Iab)/(x pi^(2)R)ln 4/3.Findout value of x.

In the figure shown two loops ABCD & EFGH are in the same plane.The sm

1.	In the figure shown two loops ABCD & EFGH are in the same plane.The smaller loop carries time varying current I=b t, where b is a positive constant and t is time.The resistance of the smalller loop is r and that of the larger loop is R.:(Neglect the self inductance of large loop) The magnetic force on the loop EFGH due to loop ABCD is (mu_(0)^(2) Iab)/(x pi^(2)R)ln 4/3.Findout value of x.
Answer» Solution :`i'=(EMF)/R=-(dphi)/(Rdt)=-(dintBds)/(Rdt)=(mu_(0)AB)/(2piR) "ln" 4/3rArrF=intBIdl=(mu_(0)^(2)Iab)/(12pi^(2)R)"ln"4/3`

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