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In the figures shown current in the long straight wire varies as `I=I_(0)((t_(0)-t)/(t_(0))` where `I_(0)` is the initial current The charge flown through resistance in the time `t_(0)` is A. `(mu_(0))/(2pi)(lbl_(0))/(R)`B. `(mu_(0))/(2pi)(ll_(0))/(R)In((b)/(a))`C. `(mu_(0))/(2pi)(ll_(0))/(R)In((a+b)/(a))`D. `(mu_(0))/(2pi)(al_(0))/(R)In((b)/(l))` |
Answer» Correct Answer - B |
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