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In the first excited state of hydrogen atom, its radius is found to be 21.2xx10^(-11) m. Calculate its Bohr radius in the ground state. Also calculate the total energy of the atom in the second excited state. |
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Answer» SOLUTION :First excited STATE means, n=2 `r_(0)=n^(2)r_(1)` `r_(1)=(21.2xx10^(-11))/(4)` `=5.3xx10^(11)m` `E=-(13.6)/(n^(2))=-3.4eV`. |
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