1.

In the first order reaction, the concentration of the reactant is reduced to 12.5% in one hour. The half-life period of the reaction is:

Answer»

15 min
30 min
20 min
3 hr

Solution :For a first order reaction,
`K = 2.303/t LOG""([A]_0)/([A]) =2.303/60log"" (100)/12.5 = 0.0346 "min"^(-1)`
Now t `1//2 = 0.693/K = 0.639/0.0346 = 20 min`.


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