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In the following circuit, what is the voltage at the source of the M1?(a) Vin * Rs / (Rs + 1/gm)(b) Vin * Rs / (Rs + gm)(c) Vin * Rs / (Rs – 1/gm)(d) Vin * Rs / (Rs + 2/gm)This question was addressed to me in an interview for job.My question comes from MOSFET Amplifier with CG Configuration in section FET Amplifiers of Analog Circuits

Answer» CORRECT option is (a) Vin * Rs / (Rs + 1/gm)

Easiest explanation: The impedance looking into the source of M1 is 1/gm. Vin experiences a potential DIVIDER before entering the source of M1. The voltage drop across Rs is TYPICALLY the voltage at the source and HENCE, it is equal to Vin * Rs / (Rs + 1/gm).


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