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In the following circuit, what is the voltage at the source of the M1?(a) Vin * Rs / (Rs + 1/gm)(b) Vin * Rs / (Rs + gm)(c) Vin * Rs / (Rs – 1/gm)(d) Vin * Rs / (Rs + 2/gm)This question was addressed to me in an interview for job.My question comes from MOSFET Amplifier with CG Configuration in section FET Amplifiers of Analog Circuits |
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Answer» CORRECT option is (a) Vin * Rs / (Rs + 1/gm) Easiest explanation: The impedance looking into the source of M1 is 1/gm. Vin experiences a potential DIVIDER before entering the source of M1. The voltage drop across Rs is TYPICALLY the voltage at the source and HENCE, it is equal to Vin * Rs / (Rs + 1/gm). |
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