1.

In the following common emitter configuration an NPN transistor with current gain beta = 100 is used . The output voltage of the amplifier will be

Answer»

10 V
0.1 V
1.0 V
10 V

Solution :`V_("INPUT")=10^(-3)V, beta=100`
`V_("out")= beta xx "Input"=100 xx10^(-3)=0.1V`


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