InterviewSolution
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InterviewSolution
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In the following diagram, the bisectors of interior angles of the parallelogram PQRS en-close a quadrilateral ABCD. Show that: (i) ∠PSB+∠SPB=90∘(ii) ∠PBS=90∘ (iii) ∠ABC=90∘(iv) ∠ADC=90∘ (v) ∠A=90∘(vi) ABCD is a rectangleThus, the bisectors of the angles of a parallelogram enclose a rectangle. |
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Answer» In the following diagram, the bisectors of interior angles of the parallelogram PQRS en-close a quadrilateral ABCD.
Show that: (i) ∠PSB+∠SPB=90∘(ii) ∠PBS=90∘ (iii) ∠ABC=90∘(iv) ∠ADC=90∘ (v) ∠A=90∘(vi) ABCD is a rectangleThus, the bisectors of the angles of a parallelogram enclose a rectangle. |
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