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In the following diagram the conducting shells are concentric .The amount of charge that flows through the switch (S) after closing it is |
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Answer» `Q`  `q_(2)-q_(1)=-2Q qQ_(1)-q_(2)+q_(3)=4Q` `RARR (q_(1))/(4piepsilon_(0))-(q_(1))/(4piepsilon_(0)(2R))+(q_(2))/(4piepsilon_(0)2R)` `-(q_(2))/(4piepsilon_(0)4R)+(q_(3))/(4piepsilon_(0)4R)` ` V_(A)(1)/(4piepsilon_(0))((q_(1)-q_(1)+q_(2)-q_(2)+q_(3)))/(4R)=V_(c)` `V_(A)=V_(C)=q_(1)-(q_(1))/(2)+q_(2)/(2)-q_(2)/(4)+(q_(3))/(4)=(q_(3))/(4)` `rArr (q_(1))/(2)+(q_(2))/(4)=0 rArr q_(2)=-2q_(1)rArr -2q_(1)-q_(1)=-2Q` `rArr q_(1)=(2Q)/(3)` rArr the charge that FLOWS through the switch is `Q//3`. |
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