1.

In the following diagram, triangle ABC is right-angled at triangle. L and M are the mid-points of side AC and AB respectively. Prove that: BL^2 + CM^2 = 5ML^2.​

Answer»

CL =AL, AM= BMSOLUTIONLM^2= AL^2+ AM^2LB^2=AL^2+ AB^2CM^2=AC^2+AM^2LM^2=AL^2+AM^2adding eq. 2 and 3LB^2+CM^2 = (AL^2+2AM^2)+(AM^2+ 2AL^2)LB^2+CM^2= 3(AL^2+AM^2)HENCE PROVED PLEASE follow me...



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