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In the following equation `CrO_(4)^(2-)+S_(2)O_(3)^(2-)+overset(ɵ)(O)Hto[Cr(OH)_(4)]^(-1)+SO_(4)^(2-)` What volume of 0.2 M `Na_(2)S_(2)O_(3)` solution.A. 30 mLB. 80 mLC. 20 mLD. 60mL |
Answer» Correct Answer - B (i). `3e^(-)+undersetunderset(x=6)(x-8=-2)(CrO_(4)^(2-))toundersetunderset(2x=12)(2x-6=-4)([Cr(OH)_(4)]^(ɵ))` Ew of ``CrO_(4)^(2-)=(Mw)/(3)` (ii). `undersetunderset(2x=4)(2x-6=-2)(S_(2)O_(3)^(2-)toundersetunderset(2x=12)(2x-6=-4)(2SO_(4)^(2-)+8e^(-)` " Eq of "`S_(2)O_(3)^(2-)=(Mw)/(8)` `N_(1)V_(1)(CrO_(4)^(2-))=N_(2)V_(2)(S_(2)O_(3)^(2-))` i.e., `m" Eq of "CrO_(4)^(2-)=m" Eq of "S_(2)O_(3)^(2-)` `V_(1)xx0.2xx3=30xx0.2xx8` `V_(1)=(30xx0.2xx8)/(0.2xx3)=80mL` |
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