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In the following gaseous phase first order reaction A_((g))to2B_((g))+C_((g)) Initial pressure was found to be 400mm and it changed to 1000mm after 20 minutes. Calculate the rate. |
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Answer» Solution :`{:(A_((g)),,to,,2B_((g)),,+,,C_((g))),(P_(i),,,,0,,,,0),((P_(1)-X),,,,2x,,,,x):}` `P_(t)=P_(i)-x+2x+x=(P_(i)+2x)` `:.x=(P_(t)-P_(i))/(2)` `:.(a-x)=P_(i)-((P_(t)-P_(i)))/(2)=(3P_(i)-P_(t))/(2)` `=(3xx400-1000)/(2)=100mm` `K=(2.303)/(t)LOG((a)/(a-x))` `=(2.303)/(20)log.(400)/(100)=0.0693min^(-1)` |
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