1.

In the following reaction 2X +B_(2)H_(6) to [BH_(2)(X)_(2)]^(+) [BH_(4)]^(-) then X will be : -

Answer»

`NH_(3)`
`CH_(3)NH_(2)`
`NaH`
All of these

Solution :When `X=H^(-), NH_(3), CH_(3)NH_(2)` then `[BH_(2)(X)_(2)]^(+) [BH_(4)]^(-)`
if `X=CO`,THF then `2[BH_(3) LARR X]`


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