1.

In the following reaction : RCH_(2)CH = CH_(2) + Icl rarr [A] Markovinkoff's product [A] is :

Answer»

`RCH_(2)underset(Cl)underset(|)(CH) - CH_(2)I`
`RCH_(2) - underset(I)underset(|)(CH) - CH_(2)Cl`
`RCH - underset(I)(CH) = CH_(2)`
`RCH = CH - CH_(2)I`

Solution :`RCH_(2)CH = CH_(2) + ICL rarr RCH_(2) - underset(Cl)underset(|)(CH) - CH_(2)I`
In ACCORDANCE with Markovnikov.s rule, more ELECTRONEGATIVE chlorine atom goes to the carbon with LESSER number of hydrogens.


Discussion

No Comment Found