In the following reaction sequence, the compound J is an intermediate. I underset(CH_(3)COONa)overset((CH_(3)CO)_(2)O)toJ underset((ii)." "SOCl_(2),(iii)." anhyd. "AlCl_(3))overset((i)." "H_(2),Pd//C)toK J(C_(9)H_(8)O_(2)) gives effervescence on treatment with NaHCO_(3) and a positive Baeyer's test. Q. The compound K is

In the following reaction sequence, the compound J is an intermediate.

1.	In the following reaction sequence, the compound J is an intermediate. I underset(CH_(3)COONa)overset((CH_(3)CO)_(2)O)toJ underset((ii)." "SOCl_(2),(iii)." anhyd. "AlCl_(3))overset((i)." "H_(2),Pd//C)toK J(C_(9)H_(8)O_(2)) gives effervescence on treatment with NaHCO_(3) and a positive Baeyer's test. Q. The compound K is
Answer» Solution :Treatment of compound (J) with `H_(2),Pd//C`, reduces the double bond to give the corresponding saturated acid, i.e., 3-henylpropanoic acid. The saturated acid on treatment with `SOCl_(2)` gives the corresponding acid chloride which upon subsequent treatment with ANHYD. `AlCl_(3)` BRINGS About CYCLIZATION to give the CYCLIC ketone, (K), i.e., I-indanone.