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In the following reaction , the initial concentration of the reactant and initial rate at 298 K are given 2 A to C + D {:([A]_(0) "mol" L^(-1) ,, "Initial rate in mol" L^(-1) s^(-1)), (0.01 ,, 5. 0 xx 10^(-5)), (0.02 ,, 2xx 10^(-4)):} The value of rate constant of this reaction at 298 K is |
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Answer» `0.01 s^(-1)` RATE = k `[A]^(alpha)` `5 xx 10^(-5) = k[0.01]^(alpha) "" … (i)` `2 xx 10^(-4) = k[0.02]^(alpha) ""… (ii)` By dividing eqn. (ii) by (i) , `(2xx 10^(-4))/(5 xx 10^(-5)) = (k[0.02]^(alpha))/(k[0.01]^(alpha))implies 4 (2)^(alpha)` i.e., `alpha = 2` Substituting the values of `alpha` in eq. (i) , `5 xx 10^(-5) = k[0.1]^(2) implies k = (5 xx 10^(-5))/(10^(-4)) = 5 xx 10^(-1) mol^(-1) L s^(-1)` |
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