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In the following reaction, three product a, b, c are obtained. H_(3)C-overset(CH_(3))overset("|")underset(CH_(3))underset("|")"C "-underset(OH)underset("|")"CH"-CH_(3)overset(H_(3)PO_(4)"/heat")rarr underset("(a)")(H_(3)-C-overset(CH_(2))overset("|")underset(CH_(3))underset("|")"C "-CH)=CH_(2)+ +H_(3)C-underset("(c)")(overset(CH_(2))overset("||")C-underset(CH_(2))underset("|")"CH"-CH_(3)) |
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Answer» `(a) 33%, (B) 64%, (C) 3%` |
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