In the following reactions: Me−CH=CH−MeBr2−−−→CCl4A2NaNH2� – InterviewSolution

1.	In the following reactions: Me−CH=CH−MeBr2−−−→CCl4A2NaNH2−−−−−→BNa/liq.NH3−−−−−−−→C The product(c) is:
Answer» In the following reactions: $M e - C H = C H - M e B r_{2} - -- \to C C l_{4} A 2 N a N H_{2} - ---- \to B N a / l i q . N H_{3} - ------ \to C$ The product(c) is:

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