In the formation of HBr from H_2 & Br_2following mechanism is observed – InterviewSolution

1.	In the formation of HBr from H_2 & Br_2following mechanism is observed. (A)Br_2hArr2Br. Equilibrium step (B)H_2+Br.toHBr+H. slow step ( C)H.+Br_2toHBr+Br. Fast step Calculate the rate of reaction, if concentration of hydrogen is twice that of bromine and the rate constant is equal to one rutherford.Concentration of bromine is 1M.
Answer» `2xx10^6` DPS `10xx10^9` dps `20.2xx10^10` dps `4xx10^2` dps Solution :1-Rutherford=`10^6` dps RATE =`K[H_2]^1[Br_2]^(1//2)` Rate = `10^6[2]^1[1]^(1//2)=2xx10^6` dps

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