1.

In the formula X=3YZ^(2),X and Z have the dimensions of capacitance and magnetic induction respectively. The dimensions of Y in MKS system are :

Answer»

`[M^(-3)L^(-2)T^(-2)A^(-4)]`
`ML^(-2)overset(@)(A)`
`[M^(-3)L^(-2)T^(8)A^(4)]`
`[M^(-3)L^(-2)T^(4)A^(-4)]`

Solution :Here `X=(Q)/(V).` But `V=(W)/(Q)`
`:.X=(Q^(2))/(W).` Now `Z=B=(F)/(IL)`
`:.Y=(X)/(3Z^(2))=(1)/(3)(Q^(2))/(W)xx(I^(2)L^(2))/(F^(2))=(A^(2)T^(2)A^(2)L^(2))/([ML^(2)T^(-2)][M^(2)L^(2)T^(-4)])`
`=[M^(-3)L^(-2)T^(8)A^(4)]`
Hence correct choice is `(c ).`


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