1.

In the fourth group, Mn(OH)_2 on heating with Pb O_2 and conc. HNO_3 gives pink colour due to the formation of

Answer»

`KMnO_(4)`
`K_(2)MnO_(4)`
`PB(MnO_(4))_(2)`
`PbMnO_(4)`

Solution :`Mn(OH)_(2) +2HNO_(3) to Mn(NO_(3))_(2) +2H_(2)O`
`2MN(NO_(3))_(2)+5PbO_(2)+6HNO_(3)`
`to underset("Purple colour")(2KMnO_(4)+5Pb(NO_(3))_(2)+2H_(2)O`


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