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In the given circuit as shown below, calculate the magnitude and direction of the current |
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Answer» SOLUTION :Effective RESISTANCE of the circuit is `R_("eff")=2+2+1=5Omega` `therefore"total current in the circuit is I"=(V_(1)-V_(2))/(R_("eff"))` `i=(10-5)/(5)=1A` Since the cell of larger emf DECIDES the direction of flow of current, the direction of current in the circuit is from A to B through e |
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