1.

In the given circuit diagram when the current reaches steady state in the circuit,the charge on the capacitor of capacitance C will be

Answer»

CE
`(CEr_1)/(r_2+r)`
`(CEr_2)/(r+r_2)`
`(CEr_1)/(r_1+r)`

Solution :The current REACHES steady state in the circuit means that the current through capacitor is zero.
ltbrlt `therefore` Current in the circuit, `i=E/(r+r_2)`
POTENTIAL difference across the capacitor,
`V_(AD)=V_(AB)=ir_2=(Er_2)/(r+r_2)`
Therefore, the charge stored in the capacitor C,
`Q=CV_(AD)=CEr_2/(r+r_2)`


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