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In the given circuit. E_(1) = 6 volts, E_(2) = 2 volts, E_(3) = 6 volts R_(1) = 6OmegaR_( 2)=2Omega R_(3) = 4Oemga, R_(4) = 3Omega and C=5muF. Find the current in R_(3) and energy stored in the capacitor at steady state |
| Answer» SOLUTION :`1.5A,14.4xx10^(6)J` | |