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In the given circuit, given that C=2MF and diode cut-in voltage, Vγ =0. Calculate the average output voltage.(a) 2V(b) 4V(c) -2V(d) -3VI have been asked this question in unit test.Asked question is from Clamper Circuit in division Diode Circuit of Analog Circuits

Answer» RIGHT option is (c) -2V

The BEST I can explain: Maximum input is Vm = 32 + 5 = 37 V

Capacitor charges up to37 – 3 = 34 V

Vout = Vin – VC = 32 + 5 sinωt – 34 = -2 + 5sinωt

Average OUTPUT voltage = – 2 V.


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