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In the given circuit it is known that the capacitor A has a capacitance of `2 muF` and carries a charge of `40 muC`. Capacitor C has a capacitance of `6 muF` and carries a charge of `180 muC`. The positive plate of both capacitors has been indicated in the Figure. Capacitance of capacitor B is `3 muF`. Calculate charge on B after the switch S is closed. |
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Answer» Correct Answer - `(240)/(11) muC` |
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