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In the given circuit the potential difference across the capacitor is 12V in steady state. Each resistor have 3Omega resistance. The emf of the ideal battery is |
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Answer» `15V` In STEADY current will not flow from the capacitor. If emf of BATTERY is `v_(0)`, then potential difference between `A` and `B` `V_(A)-V_(B)=(0.4v_(0))/5=12Vimpliesv_(0)=15V`
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