1.

In the given circuit, using a silicon BJT, what is the value of VCE?(a) 20 V(b) 15.52 V(c) 14.98 V(d) 13.97 VThe question was posed to me in a national level competition.My enquiry is from BJT DC biasing topic in portion BJT Biasing of Analog Circuits

Answer»

Correct answer is (b) 15.52 V

The EXPLANATION is: Consider the BJT to be in saturation. Then IC=20-0.2/2k=9.9 mA

And IB=20-0.8/430k=0.044 mA

IBMIN=ICSAT/β=5.09/50=0.198mA which is greater than above IB.

Hence TRANSISTOR is in the ACTIVE region.

Thus IC=βIB.

VBE=0.7V

IB=20-0.7/430=44.88μA

IC=50×44.88=2.24 mA

VCE=20-2.24*2=15.52V.



Discussion

No Comment Found

Related InterviewSolutions